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A 1.6 kg block slides freely across a rough surface such that the block slows down with an acceleration of -1.5 m/s2. What is the
coefficient Friction between the Block and the surface.

Sagot :

chibunduoyibe

Answer:

0.1531

Explanation:

a=1.5m/s^2

if you look at the image above let's assume that the object is on an inclined plane.

but because this object is on the ground, the angle is 0

a=g(sin0-ucos0)

a= -ug

-1.5= -u× 9.8

coefficient of friction= 1.5/9.8=0.1531

View image chibunduoyibe
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