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Sagot :
A of rect: L*W= 5x3= 15
A of sq= s^2= 3^2=9
He is incorrect because 15 is not double of 9, if the area of the rect is really double the area of the square then its area should be 18 not 15.
A of sq= s^2= 3^2=9
He is incorrect because 15 is not double of 9, if the area of the rect is really double the area of the square then its area should be 18 not 15.
Answer:
He is incorrect because 15 is not double of 9, if the area of the rect is really double the area of the square then its area should be 18 not 15.
Step-by-step explanation:
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