nicolliasimao
Answered

Welcome to Westonci.ca, your ultimate destination for finding answers to a wide range of questions from experts. Explore a wealth of knowledge from professionals across various disciplines on our comprehensive Q&A platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

A ball it hit straight up in the air with an initial velocity of 12.6 m/s. At what time does it cross the height of 1 m going up?

Sagot :

chibunduoyibe

Answer:

t=0.08 seconds or 2.49 seconds

Explanation:

using x= ut + 0.5at^2

x = 1

u=12.6m/s

a= -9.8m/s^2. (since it's moving upward )

1=12.6t - (0.5×9.8× t^2)

1= 12.6t - 4.9 t^2

4.9 t^2-12.6t+1=0

solving for t using quadratic formula

t=0.08 seconds or 2.49 seconds

Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.