Answered

Welcome to Westonci.ca, the ultimate question and answer platform. Get expert answers to your questions quickly and accurately. Our platform provides a seamless experience for finding reliable answers from a knowledgeable network of professionals. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

Given: ABCDis a parallelogram ∠GEC ≅ ∠HFA and AE ≅FC.
Prove △GEC ≅ △HFA.

Given ABCDis A Parallelogram GEC HFA And AE FC Prove GEC HFA class=

Sagot :

mhanifa

Answer:

  • See below

Step-by-step explanation:

Step #    Statement                               Reason                                              

2            ∠BCA ≅ ∠DAC                        Alternate interior angles

3            FA = AE + EF                            Segment addition postulate

4            CE = CF + EF                            Segment addition postulate

5            FA ≅ CE                                   Transitive property of equality

6            △GEC ≅ △HFA                       ASA postulate (two angles and the    

                                                                included side congruence)

<GEC=<HFA

As

  • AE=FC
  • A F=E C

Also

  • <BCA=<CAH(Alternative interior)

Henceforth

△GEC ≅ △HFA(ASA)

Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.