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5 < x + 3 and x + 3 ≤ 0

Sagot :

Esther

Answer:

Step-by-step explanation:

5 < x + 3

x + 3 ≤ 0

5 < x + 3

-3     -3

2 < x  =  x > 2

x + 3 ≤ 0

  - 3   - 3

x ≤ - 3

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