The area of the given shape is 65 sq. units.
What is the area of a figure?
The area of a figure is the total space enclosed within the boundary of that figure.
How is the area of a square calculated?
The area of a square is the square of its side.
How is the area of a right triangle calculated?
The area of a right triangle is the product of its two legs multiplied by half.
How to solve the question?
In the question, we are asked to find the area of the shape represented in the figure.
The given figure is a part of the square from which two right triangles are removed, the square being ABCD, and the right triangles being MND and QPC.
The area of the square ABCD, having a length of 9 units is 9*9 sq. units = 81 sq. units.
The area of the right triangle MND, having legs of lengths 3 units and 4 units is 0.5*3*4 sq. units = 6 sq. units.
The area of the right triangle QPC, having legs of lengths 4 units and 5 units is 0.5*5*4 sq. units = 10 sq. units.
Therefore, the area of the shape = 81 - 6 - 10 sq. units = 65 sq. units.
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