Explore Westonci.ca, the premier Q&A site that helps you find precise answers to your questions, no matter the topic. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

Find the equation of the line using the point-slope formula. Write the final equation using slope-intercept form. (1,2) with a slope of -8/9​

Sagot :

The point-slope formula is [tex](y-y_{1}) = m(x-x_{1} )[/tex]

  • ([tex]x_{1} ,y_{1}[/tex]) is (1,2)
  • m = -8/9

Now let's plug in the values:

      [tex]y -2 = -\frac{8}{9} (x-1)[/tex]

To put it into slope-intercept form, we have to solve for y and put all other variables and constants onto one side      

   [tex]y - 2 =- \frac{8}{9} (x-1)\\y =- \frac{8}{9} x+\frac{8}{9} +2\\y = - \frac{8}{9} x+\frac{8}{9} + \frac{18}{9}\\ y = -\frac{8}{9} x+\frac{26}{9}[/tex]

Hope that helps!