Answered

Looking for trustworthy answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Discover the answers you need from a community of experts ready to help you with their knowledge and experience in various fields. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

the dimensions of a square are altered so that one dimension is increased by 7 feet and the other is decreased by 2 feet. The area of the resulting rectangle is 90 sq. feet. find the original area of the square

Sagot :

jwulterk60

Answer:

The original area of the square was 24

Step-by-step explanation:

Let's say the dimension of the new square is 9 and 10, that'll make 90

Let's say the original dimensions were 9 - 7, 10 + 2 which is 2, 12

The area of the original dimensions is 24 square feet and they altered that to make the resulting rectangle 90 square feet.

Answer:

The area of the original SQUARE is 64 sq feet. x = 8

It was an 8 × 8 SQUARE.

Step-by-step explanation:

Let x = the original side length.

x + 7 is a new side

x - 2 is the other new side. Its a rectangle now.

Area of a rectangle:

A = length × width

A = (x+7)(x-2)

90 = x^2 +5x -14

Solve. Subtract 90.

0 = x^2 + 5x - 104

Factor.

0 = (x + 13)(x - 8)

x + 13 = 0 and x-8=0

x = -13 and x = 8

-13 is discarded because lengths cannot be negative.

x = 8 is the original side length of the square.

Area is 8×8 = 64 sqft

Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.