Answered

Westonci.ca is your trusted source for finding answers to all your questions. Ask, explore, and learn with our expert community. Explore thousands of questions and answers from a knowledgeable community of experts ready to help you find solutions. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

I don't know how to solve this problem.

I Dont Know How To Solve This Problem class=

Sagot :

suspho

Length of the rectangular photo = 22 inches

Width of the rectangular photo = 20 inches

Since, width of the frame outside the photo = x inches

Therefore, increase in length and width of the photo with frame = (x + x)

                                                                                                          = 2x inches

Length of the photo with frame = (22 + 2x) inches

Width of the photo with frame = (20 + 2x) inches

Combined Area of the photo in the frame = Length × Width

                                                                     = (22 + 2x)(20 + 2x)

                                                                     = 22(20 + 2x) + 2x(20 + 2x)

                                                                     = 440 + 44x + 40x + 4x²

                                                                     = 4x² + 84x + 440

Therefore, polynomial representing the combined area of the photo in the frame will be (4x² + 84x + 440) square inches.

If width of the frame = 4 inches

Combined area of the photo = 4(4)² + 84(4) + 440

                                                = 840 square inches

Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.