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Evaluate h(x)=-2x+9 when x=-2,0, and 5 .

h(-2)=

h(0)=

h(5)=

Sagot :

MathWiz0001

Step-by-step explanation:

Substitute the value in the parentheses into x.

When x = -2;

[tex]h( - 2) = - 2( - 2) + 9[/tex]

[tex]h( - 2) = 4 + 9[/tex]

[tex]h( - 2) = 13[/tex]

When x = 0;

[tex]h(0) = - 2(0) + 9[/tex]

[tex]h(0) = 0 +9[/tex]

[tex]h(0) = 9[/tex]

When x = 5:

[tex]h(5) = - 2(5) + 9[/tex]

[tex]h(5) = - 10 + 9[/tex]

[tex]h(5) = - 1[/tex]

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