Answered

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Lin and Kai are friends that work together on a team of 12 total people. Their manager is going to randomly
select 2 people from the team of 12 to attend a conference.

What is the probability that Lin and Kai are the 2 people chosen?

Sagot :

Using the combination formula, it is found that the probability that Lin and Kai are the 2 people chosen is of [tex]\frac{1}{66}[/tex].

The order in which the people are chosen is not important, hence the combination formula is used to solve this question.

What is the combination formula?

[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by:

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

In this problem, 2 people are chosen from a set of 12, hence:

[tex]C_{12,2} = \frac{12!}{2!10!} = 66[/tex]

Lin and Kai corresponds to one combination, hence the probability that Lin and Kai are the 2 people chosen is of [tex]\frac{1}{66}[/tex].

More can be learned about the combination formula at https://brainly.com/question/25821700

katthecat1313

Answer:

1/

12​C2​ (sorry I hope that makes sense)

Step-by-step explanation:

it was correct on khan

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