Answered

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Given: ABCDis a parallelogram ∠GEC ≅ ∠HFA and AE ≅FC.
Prove △GEC ≅ △HFA.

Given ABCDis A Parallelogram GEC HFA And AE FC Prove GEC HFA class=

Sagot :

<G E C=<H F A

A s

  • A E=F C
  • A F=E C

A lso

  • <CAH=<GCE

Hence

  • △GEC ≅ △HFA(ASA)
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