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Sagot :
Answer:
[tex]\sf x= 55.7^\circ \:[/tex]
using tan rule:
[tex]\hookrightarrow \sf tan(x) = \dfrac{opposite}{adjacent}[/tex]
[tex]\hookrightarrow \sf tan(x) = \dfrac{22}{15}[/tex]
[tex]\hookrightarrow \sf x= tan^{-1}(\dfrac{22}{15} )[/tex]
[tex]\hookrightarrow \sf x = 55.7^\circ \:[/tex]
Answer:
55.7° (nearest tenth)
Step-by-step explanation:
Use tan trig ratio:
[tex]\tan(\theta)=\dfrac{O}{A}[/tex]
where [tex]\theta[/tex] is the angle, O is the side opposite the angle and A is the side adjacent the angle.
Given:
- [tex]\theta[/tex] = [tex]x[/tex]
- O = 22
- A = 15
[tex]\implies \tan(x)=\dfrac{22}{15}[/tex]
[tex]\implies x=\arctan\left(\dfrac{22}{15}\right)[/tex]
[tex]\implies x=55.7 \textdegree[/tex]
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