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Sagot :
Answer:
x = 53.6°
using tan rule:
[tex]\hookrightarrow \sf tan(x) = \dfrac{opposite}{adjacent}[/tex]
[tex]\hookrightarrow \sf tan(x) = \dfrac{19}{14}[/tex]
[tex]\hookrightarrow \sf x = tan^{-1}(\dfrac{19}{14})[/tex]
[tex]\hookrightarrow \sf x = 53.6[/tex]
Answer:
53.6° (nearest tenth)
Step-by-step explanation:
Use tan trig ratio:
[tex]\tan(\theta)=\dfrac{O}{A}[/tex]
where [tex]\theta[/tex] is the angle, O is the side opposite the angle and A is the side adjacent the angle.
Given:
- [tex]\theta[/tex] = [tex]x[/tex]
- O = 19
- A = 14
[tex]\implies \tan(x)=\dfrac{19}{14}[/tex]
[tex]\implies x=\arctan\left(\dfrac{19}{14}\right)[/tex]
[tex]\implies x=53.6 \textdegree[/tex]
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