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m+n+ex=2m-x find x pls help me​

Sagot :

Answer:

x = [tex]\frac{m-n}{e+1}[/tex]

Step-by-step explanation:

m + n + ex = 2m - x ( add x to both sides )

m + n + ex + x = 2m ( subtract m + n from both sides )

ex + x = 2m - m - n = m - n ( factor out x from each term on the left side )

x(e + 1) = m - n ← divide both sides by (e + 1)

x = [tex]\frac{m-n}{e+1}[/tex]

m+n+ex=2m-x
x +ex=2m -m-n
x(1+e)/(1+e) =2m-m-n/(1+e)
X= 2m-m-n/(1 +e)