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O is the center of the regular dodecagon below. Find its perimeter. Round to the nearest tenth if necessary.

O Is The Center Of The Regular Dodecagon Below Find Its Perimeter Round To The Nearest Tenth If Necessary class=

Sagot :

The perimeter of the dodecagon is approx 268.7 units.

How to determine the perimeter of a regular polygon

There is the following relationship between the apothema ([tex]a[/tex]) and the side length ([tex]l[/tex]):

[tex]\tan \frac{\alpha}{2} = \frac{a}{\frac{l}{2} }[/tex]     (1)

Where [tex]\alpha[/tex] is the internal angle, in degrees.

The internal angle ([tex]\alpha[/tex]), in degrees, and perimeter ([tex]p[/tex]) are equal to the respective formulas:

[tex]\alpha = \frac{360}{n}[/tex]     (2)

[tex]p = n\cdot l[/tex]     (3)

Where [tex]n[/tex] is the number of sides.

By (1) we have an expression for [tex]l[/tex]:

[tex]l = \frac{2\cdot a}{\tan \frac{\alpha}{2} }[/tex]  

(3) in (1):

[tex]l = \frac{2\cdot a}{\tan \frac{180}{n} }[/tex] (1b)

(1b) in (3):

[tex]p = n\cdot \left(\frac{2\cdot a}{\tan \frac{180}{n} } \right)[/tex]  (3b)

If we know that [tex]a = 3[/tex] and [tex]n = 12[/tex], then the perimeter of the polygon is:

[tex]p = 12\cdot \left[\frac{2\cdot (3)}{\tan \frac{180}{12} } \right][/tex]

[tex]p \approx 268.7[/tex]

The perimeter of the dodecagon is approx 268.7 units. [tex]\blacksquare[/tex]

To learn more on polygons, we kindly invite to check this verified question: https://brainly.com/question/17756657