Welcome to Westonci.ca, the ultimate question and answer platform. Get expert answers to your questions quickly and accurately. Get immediate and reliable solutions to your questions from a knowledgeable community of professionals on our platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.
Sagot :
The volume of the rectangular package is the amount of space in the package
- The inequality that represents allowable dimensions is 4x + y ≤ P
- Three possible dimensions are: 2 by 100,1 by 104 and 1.5 by 102
The inequality that represents allowable dimensions
Let the dimension of the package be x and y.
So, the perimeter (P) and the volume (V) are
P = 4x + y
V = x²y
The maximum perimeter of the box is P.
So, the inequality is:
4x + y ≤ P
The three different dimensions
Recall that:
P = 4x + y
The perimeter becomes
4x + y = 108
Make y the subject
y = 108 - 4x
Substitute y = 108 - 4x in V = x²y
V = x²(108 - 4x)
Expand
V = 108x² - 432x
Differentiate
V' = 216x - 432
Set to 0
216x - 432 = 0
Add 432 to both sides
216x = 432
Divide by 216
x = 2
Substitute x = 2 in y = 108 - 4x
y = 108 - 4 * 2
Evaluate
y = 100
So, the inequalities are:
x ≤ 2 and y ≤ 100
Using the above inequality, three possible dimensions are: 2 by 100,1 by 104 and 1.5 by 102
Read more about maximum volumes at:
https://brainly.com/question/10373132
We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.