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Find m/_A, m/_B, m/_C for the given parallelogram

Find MA MB MC For The Given Parallelogram class=

Sagot :

Answer:

m/_A=112°, m/_B=68°, m/_C=112°

Step-by-step explanation:

m/_A is 112° since consecutive /_s in a parallelogram are supplementary therefore 180°(<- supplementary sum)-68°(<- m/_D)=112°(<- m/_A, and m/_C), and in a parallelogram, one main property is opposite /_s are congruent therefore m/_B is congruent to m/_D so m/_B=68°.

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