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Sagot :
7. Triangles KJL similar to Triangle QPR
[tex]\frac{KJ}{LJ} =\frac{QP}{RP} \\\frac{KJ}{28} =\frac{33}{42} \\KJ = \frac{33}{42} *28 =22[/tex]
8. Triangles KML similar to Triangle VTU
[tex]\frac{UT}{UV} =\frac{LM}{LK} \\\frac{UT}{60} =\frac{117}{130} \\UT =\frac{117}{130} *60\\UT=54[/tex]
Last question: Triangle CUB similar to TUS
- if both triangles are similar then the side lengths are equally
proportional
- For the picture, we see that TU is three times as long as CU
- therefore SU is three times as long as BU, and since SU is 12 then BU is 4. Therefore SB is 8
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