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Sagot :
The change in temperature if an experimenter adds 336 J of heat to a 56.2 g sample of Hg is 43.01°C.
HOW TO CALCULATE SPECIFIC HEAT CAPACITY?
The change in temperature of a substance can be calculated using the following expression;
Q = mc∆T
where;
- Q = quantity of heat absorbed or released (J)
- m = mass of substance (g)
- ∆T = change in temperature (°C)
According to this question, an experimenter adds 336 J of heat to a 56.2 g sample of Hg. The change in temperature is calculated as follows:
∆T = 336J ÷ (56.2 × 0.139)
∆T = 43.01°C
Therefore, the change in temperature if an experimenter adds 336 J of heat to a 56.2 g sample of Hg is 43.01°C.
Learn more about change in temperature at: https://brainly.com/question/2530523
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