According to the triangle:- perpendicular (p) = 8√3
hypotenuse (h) = x
[tex] \sec(60) = \frac{p}{h} [/tex]
[tex] \frac{8 \sqrt{3} }{x} = \sin(60) \\ \frac{8 \sqrt{3} }{x} = \frac{ \sqrt{3} }{2} \\ 2\times 8 \cancel{ \sqrt{3} } = x \times \cancel{ \sqrt{3} } \\ 2 \times 8 = 16 = x = hypotenuse[/tex]
Your Answer :- hypotenuse = X = 16
