Answered

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Will choose brainliest!

Using the clues provided, determine how many bills are in each envelope.

The 1st envelope has two more bills than half the number that are in the 2nd envelope.
If you double the number of notes in the 3rd envelope, it would have the same number as the 1st and 2nd together.
The 3rd envelope has more than the 1st, but fewer than the 2nd.

Sagot :

linandrew41

Lets set up some variables:

  • 1st envelope: [tex]e_{1}[/tex]
  • 2nd envelope: [tex]e_{2}[/tex]
  • 3rd envelope: [tex]e_{3}[/tex]

Now let us set up some equations based of the facts:

  • [tex]e_{1} +2=\frac{e_{2} }{2} -- > e_{2} = 2e_{1} +4[/tex]
  • [tex]2e_{3} =e_{1} +e_{2}[/tex]
  • [tex]e_{2} > e_{3} > e_{1}[/tex]

Now we could try some numbers out since there isn't really any other way I could solve this so far...

 but we do know that the sum of [tex]e_{1}[/tex] and [tex]e_{2}[/tex] must be even since they equal [tex]2e_{3}[/tex]

After you tried it out for a little bit, when [tex]e_{1}[/tex] = 2, then [tex]e_{2}[/tex] = 8, and [tex]e_{3} = 5[/tex]. These three values meet the criteria and we have our answer.

Hope that helped!

 
Dude give the guy above me Brain liest or else
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