akashii
Answered

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Special Right Trianglws

Could someone explain how to solve for each step and explain how you got there?

Special Right Trianglws Could Someone Explain How To Solve For Each Step And Explain How You Got There class=

Sagot :

chetankachana

Answer:

x = [tex]2\sqrt7[/tex]

y = [tex]2\sqrt7[/tex]

Step-by-step explanation:

Hello!

This is a right isosceles triangle (45°-45°-90°). You can solve for the missing angle by simply subtracting 45° and 90° from 180° (sum of angles in a triangle equals 180°)

Since the triangle is isosceles, x and y are congruent because they are the legs opposite to the congruent angles.

In a right isosceles triangle, the hypotenuse is always the measure of one leg multiplied by [tex]\sqrt2[/tex].

So, let's use leg y, [tex]y\sqrt2 = 2\sqrt{14}[/tex]

Solve for y:

[tex]y\sqrt2 = 2\sqrt{14}\\\\y = $\frac{2\sqrt{14}}{\sqrt2}$\\\\y = 2\sqrt7[/tex]

y = [tex]2\sqrt7[/tex], which means that x is also [tex]2\sqrt7[/tex]

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