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When the volume of a gas is
changed from m3 to 15.5 m3
the temperature will change from
159 K to 456 K.
Assume that the number of moles and the
pressure remain constant.

When The Volume Of A Gas Is Changed From M3 To 155 M3 The Temperature Will Change From 159 K To 456 K Assume That The Number Of Moles And The Pressure Remain Co class=

Sagot :

Charles law states that there is a directly proportional relationship between the volume and the temperature of the gas at certain pressure.

Therefore,

V1/T1 = V2/T2

V1 is unknown

T1 = 159K

V2 = 15.5m3

T2 = 456K

V1/159 = 15.5/456

V1 = (15.5*159)/456 = 5.404m3.

When the volume of a gas is changed from 5.404 m3 to 15.5 m3 the temperature will change from 159 K to 456 K.

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