shanofershifa
Answered

Welcome to Westonci.ca, where curiosity meets expertise. Ask any question and receive fast, accurate answers from our knowledgeable community. Experience the convenience of getting reliable answers to your questions from a vast network of knowledgeable experts. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

Find x and explain how you found it!

Find X And Explain How You Found It class=

Sagot :

VirαtKσhli

Answer:

[tex]\Large\boxed{\sf x = 19.2}[/tex]

Step-by-step explanation:

Here a right angled triangle is given to us and we need to find out the value of x . The measure of one of the sides is 24 and one of the acute angle is 53° .

  • Here 24 is hypotenuse of the triangle and x is the perpendicular .

So here we may use the ratio of sine as ,

[tex]\sf\qquad\longrightarrow sin\theta =\dfrac{p}{h} \\\\[/tex]

• On substituting the respective values ,

[tex]\sf\qquad\longrightarrow sin53^\circ =\dfrac{x}{24}\\\\[/tex]

Substitute the value of sin 53° = 4/5 ,

[tex]\sf\qquad\longrightarrow \dfrac{4}{5}=\dfrac{x}{24} \\\\[/tex]

Cross multiply ,

[tex]\sf\qquad\longrightarrow x =\dfrac{24*4}{5} \\\\[/tex]

Simplify,

[tex]\sf\qquad\longrightarrow \frak{\pink{x =19.2}} \\\\[/tex]

[tex]\rule{200}4[/tex]

Here we use trigonometric ratios

[tex]\\ \rm\hookrightarrow sin\theta=\dfrac{Perpendicular}{Hypotenuse}[/tex]

[tex]\\ \rm\hookrightarrow sin53=\dfrac{x}{24}[/tex]

[tex]\\ \rm\hookrightarrow 0.8(24)=x[/tex]

[tex]\\ \rm\hookrightarrow x=19.2[/tex]

We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.