shanofershifa
Answered

Westonci.ca is your trusted source for finding answers to all your questions. Ask, explore, and learn with our expert community. Join our Q&A platform and get accurate answers to all your questions from professionals across multiple disciplines. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

Find x and explain how you found it!

Find X And Explain How You Found It class=

Sagot :

VirαtKσhli

Answer:

[tex]\Large\boxed{\sf x = 19.2}[/tex]

Step-by-step explanation:

Here a right angled triangle is given to us and we need to find out the value of x . The measure of one of the sides is 24 and one of the acute angle is 53° .

  • Here 24 is hypotenuse of the triangle and x is the perpendicular .

So here we may use the ratio of sine as ,

[tex]\sf\qquad\longrightarrow sin\theta =\dfrac{p}{h} \\\\[/tex]

• On substituting the respective values ,

[tex]\sf\qquad\longrightarrow sin53^\circ =\dfrac{x}{24}\\\\[/tex]

Substitute the value of sin 53° = 4/5 ,

[tex]\sf\qquad\longrightarrow \dfrac{4}{5}=\dfrac{x}{24} \\\\[/tex]

Cross multiply ,

[tex]\sf\qquad\longrightarrow x =\dfrac{24*4}{5} \\\\[/tex]

Simplify,

[tex]\sf\qquad\longrightarrow \frak{\pink{x =19.2}} \\\\[/tex]

[tex]\rule{200}4[/tex]

Here we use trigonometric ratios

[tex]\\ \rm\hookrightarrow sin\theta=\dfrac{Perpendicular}{Hypotenuse}[/tex]

[tex]\\ \rm\hookrightarrow sin53=\dfrac{x}{24}[/tex]

[tex]\\ \rm\hookrightarrow 0.8(24)=x[/tex]

[tex]\\ \rm\hookrightarrow x=19.2[/tex]

Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.