O43431am
Answered

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any1 know the answer?

Any1 Know The Answer class=

Sagot :

Answer:

Don't agree with Diego.

Step-by-step explanation:

When x=5,

[tex]10 + {x}^{2} = 10 + {5}^{2} = 35 \\ {2}^{x} = {2}^{5} = 32[/tex]

35>32

When x=6,

[tex]10 + {x}^{2} = 10 + {6}^{2} = 46 \\ {2}^{x} = {2}^{6} = 64[/tex]

Obviously, 46<64

When x=7,

[tex]10 + {x}^{2} = 10 + {7}^{2} = 59 \\ {2}^{x} = {2}^{7} = 128[/tex]

Obviously, 59<128

Hence, conclusion

When

[tex]x \geqslant 6[/tex]

[tex]10 + {x}^{2} \leqslant {2}^{x} [/tex]

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