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Sagot :
Answer:
368.92g
Explanation:
Firstly, let's balance the equation which is
2NO + O₂ ---> 2NO₂
Starting with 8.02 mol of NO let's calculate the moles of oxygen which is in a 2 : 1 molar ratio
2NO + O₂
2 : 1
8.02 mol : x mol
Moles of O₂ = 8.02 ÷ 2 = 4.01 mol
Doing the same thing for 18.75 mol of O₂ to calculate the number of moles of NO
2NO + O₂
2 : 1
x mol : 18.75 mol
Moles of NO = 18.75 × 2 = 37.5 however we are told we have 8.02 moles of NO, so we are unable to use 18.75 mol of O₂
Using 8.02 mol of NO to figure out the number of moles of NO₂ :
2NO : 2NO₂
They have the same molar ratio of 2 : 2, so the number of moles is 8.02
Using formula moles = mass / Molar mass
Rearranging to find mass = moles × molar mass
Molar mass of NO₂ = 14 + 16 + 16 = 46
Mass = 46 × 8.02 = 368.92g
Reaction:
2NO + O₂ → 2NO₂
determine the limiting reactant from the ratio of moles to the reaction coefficient
NO : O₂ = 8.02/2 : 18.75/1 = 4.01 : 18.75
NO as a limiting reactant (smaller ratio)
so mole NO₂ from limiting reactant (NO) :
= 2/2 x mole NO
= 2/2 x 8.02
= 8.02
mass NO₂ = mole x molar mass NO₂ = 8.02 x 46 g/mole = 368.92 g
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