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please help me i would greatly appreciate it.. 50 points and will mark brainliest

Please Help Me I Would Greatly Appreciate It 50 Points And Will Mark Brainliest class=

Sagot :

indrawboy

Reaction

CaO (s) + H₂O (l) ⇒ Ca(OH)₂ (s)

The first step is to find the limiting reactant

mole CaO = mass : molar mass = 25.4 g : 56 g/mole = 0.453

mole H₂O = 13.5 g : 18 g/mole = 0.75

because the reaction coefficients of CaO  and H₂O are the same in the equation above, the limiting reactant is determined from the smallest number of moles

So CaO is the limiting reactant (0.453 < 0.75)

then the moles of product Ca(OH)₂ are determined from the moles of limiting reactant (CaO)

mole Ca(OH)₂ =  mole CaO (the reaction coefficient is the same, 1:1) = 0.453

then mass Ca(OH)₂ produced = mole x molar mass = 0.453 x 74 g/mole = 33.522 g

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