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Sagot :
Reaction
CaO (s) + H₂O (l) ⇒ Ca(OH)₂ (s)
The first step is to find the limiting reactant
mole CaO = mass : molar mass = 25.4 g : 56 g/mole = 0.453
mole H₂O = 13.5 g : 18 g/mole = 0.75
because the reaction coefficients of CaO and H₂O are the same in the equation above, the limiting reactant is determined from the smallest number of moles
So CaO is the limiting reactant (0.453 < 0.75)
then the moles of product Ca(OH)₂ are determined from the moles of limiting reactant (CaO)
mole Ca(OH)₂ = mole CaO (the reaction coefficient is the same, 1:1) = 0.453
then mass Ca(OH)₂ produced = mole x molar mass = 0.453 x 74 g/mole = 33.522 g
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