Discover a wealth of knowledge at Westonci.ca, where experts provide answers to your most pressing questions. Get quick and reliable solutions to your questions from knowledgeable professionals on our comprehensive Q&A platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

please help me i would greatly appreciate it.. 50 points and will mark brainliest

Please Help Me I Would Greatly Appreciate It 50 Points And Will Mark Brainliest class=

Sagot :

Reaction

CaO (s) + H₂O (l) ⇒ Ca(OH)₂ (s)

The first step is to find the limiting reactant

mole CaO = mass : molar mass = 25.4 g : 56 g/mole = 0.453

mole H₂O = 13.5 g : 18 g/mole = 0.75

because the reaction coefficients of CaO  and H₂O are the same in the equation above, the limiting reactant is determined from the smallest number of moles

So CaO is the limiting reactant (0.453 < 0.75)

then the moles of product Ca(OH)₂ are determined from the moles of limiting reactant (CaO)

mole Ca(OH)₂ =  mole CaO (the reaction coefficient is the same, 1:1) = 0.453

then mass Ca(OH)₂ produced = mole x molar mass = 0.453 x 74 g/mole = 33.522 g

Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.