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Sagot :
Area=45 cm2
Explanation:
Let the length be L
and the width be W (with all measurements in cm.)
We are told that L=W+4
and
that the perimeter is 28
Since the perimeter of a rectangle is 2(L+W)
we have
XXX2(L+W)=28
XXX2(W+4+W)=28
XXX2(2W+4)=28
XXX(2W+4)=14
XXX2W=10
XXXW=5
and since L=W+4
XXXL=9
Finally
XXXArea=L×W=9×5=45 (sq.cm
Answer :
- Value of x is 1.5 cm
Explaination :
In the question it is given that the length is 4 cm more than the width so let us assume the width as x.
Therefore,
- Length (l) = 4 + x
- Breadth = x
As we know the formula of calculating the perimeter of rectangle is,
- P = 2 (l + b)
Here,
- P is perimeter
- l is length
- b is breadth
Putting their respective values,
=> 14 = 2 (x + 4 + x)
=> 14 = 2 × (x + 4 + x)
=> 14 = 2x + 8 + 2x
=> 14 = 4x + 8
=> 14 - 8 = 4x
=> 4x = 6
=> x = 6 / 4
=> x = 3 / 2
=> x = 1.5
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