Answered

Discover answers to your questions with Westonci.ca, the leading Q&A platform that connects you with knowledgeable experts. Our platform provides a seamless experience for finding precise answers from a network of experienced professionals. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

BRAINLIEST :
In this rectangle, the length is 4 cm more than the width. The perimeter is 14cm. Find the value of 'x’

Sagot :

lakshmikatta883

Area=45 cm2

Explanation:

Let the length be L

and the width be W (with all measurements in cm.)

We are told that L=W+4

and

that the perimeter is 28

Since the perimeter of a rectangle is 2(L+W)

we have

XXX2(L+W)=28

XXX2(W+4+W)=28

XXX2(2W+4)=28

XXX(2W+4)=14

XXX2W=10

XXXW=5

and since L=W+4

XXXL=9

Finally

XXXArea=L×W=9×5=45 (sq.cm

ItzStarzMe

Answer :

  • Value of x is 1.5 cm

Explaination :

In the question it is given that the length is 4 cm more than the width so let us assume the width as x.

Therefore,

  • Length (l) = 4 + x
  • Breadth = x

As we know the formula of calculating the perimeter of rectangle is,

  • P = 2 (l + b)

Here,

  • P is perimeter
  • l is length
  • b is breadth

Putting their respective values,

=> 14 = 2 (x + 4 + x)

=> 14 = 2 × (x + 4 + x)

=> 14 = 2x + 8 + 2x

=> 14 = 4x + 8

=> 14 - 8 = 4x

=> 4x = 6

=> x = 6 / 4

=> x = 3 / 2

=> x = 1.5

___________________________

We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.