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A reversible reaction is represented by the equation above. The amounts of reactants and products at time 1 are shown in the particle diagram on the left. The particle diagram on the right shows the amounts of reactants and products at time 2. Based on the diagrams, what can be inferred about the relative rates of the forward and reverse reactions between time 1 and time 2 ?

Sagot :

The observation made from the reaction is that  The forward reaction is more productive than the Reverse reaction.

What can be inferred about the relative rates of the forward and reverse reactions between time 1 and time 2?

Generally, the equation for the   is mathematically given as

2X_(g)+y_2(g)---->2xy(g)

Therefore

From the observation of this chemical equation, we see that the rate of formed reaction is greater than the rate of the reverse reaction.

We see that More XY is formed at the LHS than at the RHS of the equation

In conclusion

The forward reaction is more productive than the Reverse reaction

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Complete Question

Time 1 Time 2 [•=X P=Y₂ 0 = xr 2 X(g) + Y2(g) = 2 XY (9) A reversible reaction is represented by the equation above. The amounts of reactants and products at time 1 are shown in the particle diagram on the left. The particle diagram on the right shows the amounts of reactants and products at time 2. Based on the diagrams, what can be inferred about the relative rates of the forward and reverse reactions between time 1 and time 2 ? Nothing can be inferred because the total number of X and Y atoms is the same in each diagram. Nothing can be inferred because the temperature of the system may have been changed. The rate of the reverse reaction is greater than the rate of the forward reaction. The rate of the forward reaction is greater than the rate of the reverse reaction

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