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A fast teaub abd a ski train driving from city a and city b face to face the fast train has a speed of 76km/h, the slow train has a speed of 65km/h. The fast train ent 40km more than the slow train when they met. The distance between the two cities is ___km

Sagot :

onyebuchinnaji

The distance between the two cities is 513.24 km.

Time of motion when the two trains meet

The time spent on the journey when the two trains meet is calculated as follows;

(Va - Vb)t = d

where;

  • d is the distance between the trains before meeting

(76 - 65)t = 40

11t = 40

t = 40/11

t = 3.64 hr

Distance traveled by the fast train

d1 = 76 km/h x 3.64 h

d1 = 276.64 km

Distance traveled by the slow train

d2 = 65 km/h x 3.64 h

d2 = 236.6 km

The distance between the two cities = 276.64 km + 236.6 km

                                                             = 513.24 km

Learn more about relative velocity here: https://brainly.com/question/17228388

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