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The perimeter of a rectangle is 84. If the length is 2 more than three times the width, what are the dimensions of the rectangle? Show how you represent the unknown and create the equation. *

Sagot :

The perimeter solved shows that the dimensions of the rectangle are 32 and 10.

How to calculate the perimeter

Let the width be w

Length = 3w + 2

Perimeter = 2(length + width)

Perimeter = 2(3w + 2) + 2w

6w + 4 + 2w = 84

8w + 4 = 84

8w = 84 - 4

w = 80/8

w = 10

Length = 3w + 2

Length = 3(10) + 2

Length = 32

The dimensions of the rectangle are 32 and 10.

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