Answered

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Simplify the sum.

[tex]\frac{d^2-9d+18}{d^2+2d-15} +\frac{d^2-2d-8}{d^2+5d+6}[/tex]

o [tex]\frac{2d^2+4d-38}{(d+5)(d+3)}[/tex]
o [tex]\frac{d^2-2d-38}{(d+5)(d+3)}[/tex]
o [tex]\frac{2d^2+4d-38}{(d+5)(d+3)}[/tex]
o [tex]\frac{2d^2-2d-38}{(d+5)(d+3)}[/tex]


Sagot :

Answer:

B is correct!!

Step-by-step explanation:

Would be a long explanation. Do u want the explanation.