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A truck speed from rest to 120km/h in 13s. Find its acceleration. (convert to m/s)

Sagot :

ganjilaya2019

answer:

2.5 m/s²

Explanation:

120 km/h = 120 ÷ 3.6 = 100/3 ≈ 33 m/s

a = (v2 - v1)/∆t = (33m/s - 0)/ 13s = 33/13 m/s²≈ 2.5 m/s²

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