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Sagot :
Answer:
1.41
Step-by-step explanation:
Since we are only focusing on Linda's SAT score, we only need to use the SAT distribution information.
We know that our mean is [tex]\mu=511[/tex] and our standard deviation is [tex]\sigma=120[/tex] with observed value [tex]x=680[/tex]
Our formula for the standardized score (also known as the z-score) is [tex]z=\frac{x-\mu}{\sigma}[/tex] which tells us how many standard deviations [tex]\sigma[/tex] above or below the mean [tex]\mu[/tex] the observed value of [tex]x[/tex] is:
[tex]z=\frac{x-\mu}{\sigma}\\\\z=\frac{680-511}{120}\\\\z\approx1.41[/tex]
Therefore, Linda's standardized score is 1.41, which means she scored 1.41 standard deviations above the mean.
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