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Sagot :
The computation of the p-value that is true is; The population proportion of adults who watch 15 or fewer hours of television per week is less than 0.30.
What is the p-value of the hypothesis?
Let the proportion of adults watching television less than or equal to 15% be x
30 percent of adults in the united states watch 15 or fewer hours of television per week. Thus;
Null Hypothesis; H₀: x = 30% = 0.30
Alternative Hypothesis; H₁ : x < 30% , or x < 0.30
Formula for the z-score is:
z = p' - [√{p₀(1 - p₀)/n}]
where;
p' = 0.28, p₀ = 0.30, p₁ = 0.70
Using online p-value from z-score calculator we have;
p(z < -1.543) = 0.061
If we assume 10% level of significance, i.e p = 0.10
Thus, p-value 0.061 < 0.10 and we reject Null hypothesis and accept the alternative hypothesis.
Finally, we conclude that the proportion of adults watching television less than or equal to 15% < 30% or 0.30'
Read more about Confidence Intervals at; https://brainly.com/question/16362968
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