Answered

Westonci.ca is the Q&A platform that connects you with experts who provide accurate and detailed answers. Join our platform to get reliable answers to your questions from a knowledgeable community of experts. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

If a town with a population of 10,000 doubles in size every 17 years. What will the population be 68 years from now?

Sagot :

linandrew41

Let us set up the equation:

[tex]total population = 10000*(2)^{68/17}=10000*(2^4)=160000[/tex] people

  • 10000 is the initial population
  • 2 is the rate at which the population grows
  • 68/17 is the number of periods that the population grows

Hope that helps!

abiolataiwo2015

Assuming a town with a population of 10,000 doubles in size every 17 years. The population  68 years from now is 160,000.

Population

P(t) = 10000×2t/12

Where:

t=time;  k is a constant

P(68) = 10000×2^68/12

P(68) = 10000×2^4

P(68) = 10000×16

P(68) = 160,000

Inconclusion assuming a town with a population of 10,000 doubles in size every 17 years. The population  68 years from now is 160,000.

Learn more about population here:https://brainly.com/question/25630111

Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.