Answered

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Solve the following problem ~

[tex] \sf ^8P_3= \mathrm{}?[/tex]
​

Sagot :

Answer:

[tex]336[/tex]

Step-by-step explanation:

[tex]8p3[/tex]

Divide the first number's factorial by the factorial of the second number subtracted from the first number.

By permutation formula: [tex]np_r=\frac{n!}{(n-r)!}[/tex] and Since n=8 and r=3 we can substitute the values and solve,

[tex]_np_r=\frac{n!}{(n-r)!}=\frac{8}{(8-3)!} =\frac{8*7*6*5*3*3*2*1}{5*4*3*2*1}[/tex]

[tex]8*7*6=336[/tex]

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