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The maximum volume flow rate of kerosene is 8.3 L/s
What is the maximum volume flow rate?
In fluid dynamics, the maximum volume flow rate (Q) is the volume or amount of fluid flowing via a required cross-sectional area per unit time.
In fluid mechanics, using the following relation, we can determine the maximum volume flow rate of kerosene.
- Power = mass flow rate(m) × specific work(w) --- (1)
- Specific work = acceleration due to gravity (g) × head (h) ---- (2)
- Mass flow rate (m) = density (ρ) × volume flow rate (Q) --- (3)
By combining the three equations together, we have:
The power gained through the fluid pump to be:
- P = ρ × Q × g × h
Making Q the subject, we have:
[tex]\mathbf{Q = \dfrac{P}{\rho \times g \times h}}[/tex]
where:
- P = 2 kW = 2000 W
- ρ = 0.820 kg/L
- g = 9.8 m/s
- h = 30 m
[tex]\mathbf{Q = \dfrac{2000 \ W }{820 \ kg/m^3 \times 9.8 m/s \times 30 \ m}}[/tex]
Q = 0.008296 m³/s
Q ≅ 8.3 L/s
Learn more about the maximum volume flow rate here:
https://brainly.com/question/19091787
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