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Sagot :
Answer:
- Given and Explained Below.
Explanation:
- [tex]\sf sin(x)= \dfrac{opposite}{hypotensue}[/tex]
- [tex]\sf cos(x)= \dfrac{adjacent}{hypotensue}[/tex]
- [tex]\sf tan(x)= \dfrac{opposite}{adjacent}[/tex]
using the formula's:
[tex]\sf sin(T)= \dfrac{t}{v}[/tex]
[tex]\sf cos(T)= \dfrac{u}{v}[/tex]
[tex]\sf cos(U)= \dfrac{t}{v}[/tex]
[tex]\sf sin(U)= \dfrac{u}{v}[/tex]
Answer:
[tex]\mathsf{\sin T=\dfrac{t}{v} \ \ \ \cos T=\dfrac{u}{v}}\\\\\mathsf{\cos U=\dfrac{t}{v} \ \ \ \sin U=\dfrac{u}{v}}[/tex]
Step-by-step explanation:
Trig ratios:
[tex]\mathsf{\sin(\theta)=\dfrac{O}{H} \ \ \ \cos(\theta)=\dfrac{A}{H} \ \ \ \tan(\theta)=\dfrac{O}{A}}[/tex]
(where [tex]\theta[/tex] is the angle, O is the side opposite the angle, A is the side adjacent the angle and H is the hypotenuse of a right triangle)
[tex]\mathsf{\sin T=\dfrac{t}{v} \ \ \ \cos T=\dfrac{u}{v}}\\\\\mathsf{\cos U=\dfrac{t}{v} \ \ \ \sin U=\dfrac{u}{v}}[/tex]
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