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Determine the number of moles in 154g of Li2CO3

Sagot :

Ankit

Given:

Weight of Li2CO3 = 154 g

To find:

number of moles of Lithium Carbonate Li2CO3 = ?

Solution:

first we have to calculate the molar mass of Lithium Carbonate,

The elemental composition of Li2CO3

Li = 2 units, Atomic weight of each Li atom is 7 g/mol

Li = 2 × 7 = 14 g/mol

C = 1 unit, Atomic weight of Carbon is 12 g/mol

O = 3 units, Atomic weight of each O atom is 16 g/mol

O = 3 × 16 = 48 g/mol

Atomic weight of Li2CO3 = 14+12+48 = 72 g/mol

now,

[tex]number \: of \: moles = \: \frac{Given \: weight \: of \: substance}{Atomic \: weight \: of \: substance} [/tex]

Number of moles = 154/72 = 2.14 moles

Answer- The number of moles of Lithium Carbonate is 2.14

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