ileyng14
Answered

Find the best solutions to your questions at Westonci.ca, the premier Q&A platform with a community of knowledgeable experts. Experience the ease of finding reliable answers to your questions from a vast community of knowledgeable experts. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

A model rocket is launched with an initial upward velocity of 126 ft/s. The rocket's height h (in feet) after 1 seconds is given by the following
=126t-16t^2
Find all values of t for which the rocket's height is 50 feet.
Round your answers) to the nearest hundredth.
(If there is more than one answer, use the "or" button.)

Sagot :

reinhard10158

Step-by-step explanation:

f(t) = -16t² + 126t

for what values of t did this function deliver 50 ft of height ?

50 = -16t² + 126t

-16t² + 126t - 50 = 0

the general solution to such a squared equation is

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case

x = t

a = -16

b = 126

c = -50

t = (-126 ± sqrt(126² - 4×-16×-50))/(2×-16) =

= (-126 ± sqrt(15876 - 3200))/-32 =

= (-126 ± sqrt(12676))/-32 =

= (-126 ± 112.5877436...)/-32

t1 = (-126 + 112.5877436...)/-32 = -13.41225644.../-32 =

= 0.419133014... ≈ 0.42 seconds

t2 = (-126 - 112.5877436...)/-32 = -238.5877436.../-32 =

= 7.455866986... ≈ 7.46 seconds

so, this means, right after launch the ticket reaches 50ft (from below) after 0.42 seconds, and then, when it falls back down, it will reach 50ft again (this time from above) after 7.46 seconds of flight time.

We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.