ileyng14
Answered

Welcome to Westonci.ca, the place where your questions find answers from a community of knowledgeable experts. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

A model rocket is launched with an initial upward velocity of 126 ft/s. The rocket's height h (in feet) after 1 seconds is given by the following
=126t-16t^2
Find all values of t for which the rocket's height is 50 feet.
Round your answers) to the nearest hundredth.
(If there is more than one answer, use the "or" button.)

Sagot :

reinhard10158

Step-by-step explanation:

f(t) = -16t² + 126t

for what values of t did this function deliver 50 ft of height ?

50 = -16t² + 126t

-16t² + 126t - 50 = 0

the general solution to such a squared equation is

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case

x = t

a = -16

b = 126

c = -50

t = (-126 ± sqrt(126² - 4×-16×-50))/(2×-16) =

= (-126 ± sqrt(15876 - 3200))/-32 =

= (-126 ± sqrt(12676))/-32 =

= (-126 ± 112.5877436...)/-32

t1 = (-126 + 112.5877436...)/-32 = -13.41225644.../-32 =

= 0.419133014... ≈ 0.42 seconds

t2 = (-126 - 112.5877436...)/-32 = -238.5877436.../-32 =

= 7.455866986... ≈ 7.46 seconds

so, this means, right after launch the ticket reaches 50ft (from below) after 0.42 seconds, and then, when it falls back down, it will reach 50ft again (this time from above) after 7.46 seconds of flight time.

Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.