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please hurry find DCB

Please Hurry Find DCB class=

Sagot :

Answer:

∠DCB = 102°

Explanation:

∠CDB = ∠CBD

∠DCB = 180° - ∠CBD - ∠CDB

∠DCB = 180° - 39° - 39°

∠DCB = 102°

the answer is the angle is 102°
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