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Write the equation of a line that is parallel to y = 2x + 5 and goes through the point (6,1)

Sagot :

slope of parallel line: 2

y = 2x + b

1 = 2(6) + b

1 = 12 + b

b = -11

equation of parallel line: y = 2x -11

Solution:

Since the original line is parallel to y = 2x + 5, the original line's slope must be 2.

Using point slope form:

  • y - y₁ = m(x - x₁)
  • => y - 1 = 2(x - 6)
  • => y - 1 = 2x - 12
  • => y = 2x - 11

The equation of a line that is parallel to y = 2x + 5 and goes through the point (6, 1) is y = 2x - 11.

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