Get the answers you need at Westonci.ca, where our expert community is always ready to help with accurate information. Discover in-depth answers to your questions from a wide network of experts on our user-friendly Q&A platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
S + O2 → SO2
Moles of S:
11/32.06 = 0.3431 mol
Moles of O2:
44/15.999 = 2.75 mol
Sulfur will be the limiting reagent.
Oxygen will be the excess reagent
2.75 - 0.3431 = 2.4071 mols of oxygen leftover
2.4071 * 15.999 = 38.511
38.511 grams of oxygen will be leftover
Reaction
S + O₂ ⇒ SO₂
mole S = 11 : 32 g/mol = 0.34375
mole O₂ = 44 : 32 g/mol = 1.375
S as a limiting reactant (smaller) and converted all to sulfur dioxide
mole O₂ (unreacted) = 1.375 - 0.34375 = 1.03125
mass O₂ (unreacted) = 1.03125 x 32 = 33 g
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.