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Sagot :

The maximum amount of H2O that can form is 0.07125 mole

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2H₂ + O₂ ⇒ 2H₂O

mole H₂ = 17.14 : 2 g/mole = 8.57

mole O₂ = 1.14 L : 32 g/mole = 0.0356

O₂ as a limiting reactant (smaller mol ratio)

mole H₂O = 2/1 x mole O₂ = 2/1 x 0.0356 = 0.0712

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