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Sagot :
The maximum amount of H2O that can form is 0.07125 mole
Reaction
2H₂ + O₂ ⇒ 2H₂O
mole H₂ = 17.14 : 2 g/mole = 8.57
mole O₂ = 1.14 L : 32 g/mole = 0.0356
O₂ as a limiting reactant (smaller mol ratio)
mole H₂O = 2/1 x mole O₂ = 2/1 x 0.0356 = 0.0712
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