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Sagot :

Balanced chemical equation: 2H2 + O2 → 2H2O

The limiting reagent will be H2

All 10.39 mol of H2 will be used up produce 10.39 mol of H20

The excess reagent will be O2 and there will be 5.78 mols left over

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Explanation:

The balance chemical equation is

2H2+O2—>2H2O

The limiting reactant is found by dividing the moles of each reactant by its coefficient

For H2=10.39/2=5.195

For O2=16.17/1= 16.17

Since H2 has the smaller value it’s the limiting reactant

The mass of the maximum amount of H2O is found by using the formula

moles= mass/molar mass

solving for mass gives

mass= moles*molar mass

(molar mass of H2O= 18g/mol)

mass= 5.195*18=93.51grams of H2O

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