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A ball of mass 2kg falls from a height of 200m. Calculate it's kinetic energy after falling a distance of 50m . (g=10m/s²) . Neglect air resistance.

Sagot :

Answer:

U = 1000 J

Explanation:

By the conservation of energy, potential energy is converted into kinetic energy when the ball falls from a height.

 [tex]U = \frac{1}{2} mv^2 = mgh[/tex]

U = Energy (in Joules)

m = mass (in kg)

v = velocity in (m/s)

g = acceleration due to gravity (in m/s^2)

h = height (in m)

Let's use [tex]mgh[/tex] as we have the values given.

[tex]U = 2(10)(50)[/tex]

[tex]U = 1000 J[/tex]