Westonci.ca is your trusted source for accurate answers to all your questions. Join our community and start learning today! Our platform provides a seamless experience for finding precise answers from a network of experienced professionals. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
Are produced 72 grams of water in this reaction.
Mole calculation
To find the value of moles of a product from the number of moles of a reactant, it is necessary to observe the stoichiometric ratio between them:
[tex]Ca(OH)_2 + 2HCl = > 2H_2O + CaCl_2[/tex]
Analyzing the reaction, it is possible to see that the stoichiometric ratio is 1:2, so we can perform the following expression:
[tex]MM_{Ca(OH)_2} = 74.1g/mol[/tex]
[tex]MM = \frac{g}{mol}[/tex]
[tex]74.1 = \frac{35.8}{mol}\\mol = 2[/tex]
So, if there are 2 mols of Ca(OH)2:
Ca(OH)2 | H2O
[tex]\frac{1mol}{2mol} =\frac{2mol}{xmol}[/tex]
[tex]x = 4mol[/tex]
Finally, just find the number of grams of water using your molar mass:
[tex]MM_{H_2O} = 18g/mol[/tex]
[tex]18= \frac{m}{4}\\m = 72g[/tex]
So, 72 grams are produced of water in this reaction.
Learn more about mole calculation in: brainly.com/question/2845237
Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.
