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Sagot :
Are produced 72 grams of water in this reaction.
Mole calculation
To find the value of moles of a product from the number of moles of a reactant, it is necessary to observe the stoichiometric ratio between them:
[tex]Ca(OH)_2 + 2HCl = > 2H_2O + CaCl_2[/tex]
Analyzing the reaction, it is possible to see that the stoichiometric ratio is 1:2, so we can perform the following expression:
[tex]MM_{Ca(OH)_2} = 74.1g/mol[/tex]
[tex]MM = \frac{g}{mol}[/tex]
[tex]74.1 = \frac{35.8}{mol}\\mol = 2[/tex]
So, if there are 2 mols of Ca(OH)2:
Ca(OH)2 | H2O
[tex]\frac{1mol}{2mol} =\frac{2mol}{xmol}[/tex]
[tex]x = 4mol[/tex]
Finally, just find the number of grams of water using your molar mass:
[tex]MM_{H_2O} = 18g/mol[/tex]
[tex]18= \frac{m}{4}\\m = 72g[/tex]
So, 72 grams are produced of water in this reaction.
Learn more about mole calculation in: brainly.com/question/2845237
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