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Sagot :
X = 55.71 degrees
sin(β) = b / c so β = arcsin(b / c) (inverse sine)
cos(β) = a / c so β = arccos(a / c) (inverse cosine)
tan(β) = b / a so β = arctan(b / a) (inverse tangent)
cot(β) = a / b so β = arccot(a / b) (inverse cotangent) :)
sin(β) = b / c so β = arcsin(b / c) (inverse sine)
cos(β) = a / c so β = arccos(a / c) (inverse cosine)
tan(β) = b / a so β = arctan(b / a) (inverse tangent)
cot(β) = a / b so β = arccot(a / b) (inverse cotangent) :)
Answer:
[tex]\sf x= 55.7[/tex]
using tan rule:
[tex]\sf tan(x)= \dfrac{opposite}{adjacent}[/tex]
using the formula:
[tex]\sf tan(x)= \dfrac{22}{15}[/tex]
[tex]\sf x= tan^{-1}(\dfrac{22}{15})[/tex]
[tex]\sf x= 55.7[/tex]
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